(2x-5)^2/2=-9

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Solution for (2x-5)^2/2=-9 equation: 


x in (-oo:+oo)

((2*x-5)^2)/2 = -9 // + 9

((2*x-5)^2)/2+9 = 0

((2*x-5)^2)/2+(2*9)/2 = 0

(2*x-5)^2+2*9 = 0

4*x^2-20*x+43 = 0

4*x^2-20*x+43 = 0

4*x^2-20*x+43 = 0

DELTA = (-20)^2-(4*4*43)

DELTA = -288

DELTA < 0

1 = 0

1/2 = 0

1/2 = 0 // * 2

1 = 0

1 = 0

x belongs to the empty set

x belongs to the empty set

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